This is a CAD dwg drawing for Steel Frame Elevator Shaft Details. Multi-storey lift steel frame with four corner columns, lateral bracing beams at each floor level on all sides and vertical diagonal bracing on 3 sides apart from the elevator door opening side. Each of our tutorials comes with a handy directed drawing printable with all the steps included, as well as room to make your drawing. Perfect for getting artsy on the go or to use in the classroom (you could also bind them in your own personal book to practice). Here are our latest how to draw tutorials: Magical Creatures.
1. The problem statement, all variables and given/known data
A man is on an elevator
- Draw a FBD of the man if the elevator accelerates upwards
- Draw an FBD of the man if ele. accelerates downwards
2. Relevant equations
F=m*a
w=mg
3. The attempt at a solution
My FBD For the first one 'elevator accelelartes upwards' means that the net force must point upwards, the only two forces acting are the normal force and the weight force. I know that when you go up the elevator you should feel heavier, which is measuring the magnitude of the normal force
So the normal force will have a greater magnitude pointing 'up' and the weight force will be a smaller arrow pointing down.. as so..
/
|
|
| Normal force
_
|
/Weight force
The second part will be opposite, so you will have a smaller normal force and greater weight force, and will feel lighter than usual because of a smaller normal force acting on you.
First part given by n= may +w
second n=-may +w
Is this correct? is something wrong here?
Thanks
A man is on an elevator
- Draw a FBD of the man if the elevator accelerates upwards
- Draw an FBD of the man if ele. accelerates downwards
2. Relevant equations
F=m*a
w=mg
3. The attempt at a solution
My FBD For the first one 'elevator accelelartes upwards' means that the net force must point upwards, the only two forces acting are the normal force and the weight force. I know that when you go up the elevator you should feel heavier, which is measuring the magnitude of the normal force
So the normal force will have a greater magnitude pointing 'up' and the weight force will be a smaller arrow pointing down.. as so..
/
|
|
| Normal force
_
|
/Weight force
The second part will be opposite, so you will have a smaller normal force and greater weight force, and will feel lighter than usual because of a smaller normal force acting on you.
First part given by n= may +w
second n=-may +w
Is this correct? is something wrong here?
Thanks